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disa [49]
4 years ago
12

(x^3+43-49x-7x^2)/(x^2-49)

Mathematics
2 answers:
GaryK [48]4 years ago
7 0
(X-7) is an answer and -300 is the reminder
liraira [26]4 years ago
7 0

Answer:

Quotient = x - 7,

Remainder = -300.

Step-by-step explanation:

Here, the given expression,

\frac{x^3+43-49x-7x^2}{x^2-49}

=\frac{x^3-7x^2-49x+43}{x^2-49}

By the long division ( shown below ), we get,

\frac{x^3-7x^2-49x+43}{x^2-49}=x-7-\frac{300}{x^2-49}

Hence, in the given division problem,

Quotient = x - 7,  

Remainder = -300.

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Omg guys I need help with this question I've failed the test like 4 time because of this question and I give up. Can someone ple
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Answer:

D. 270

Step-by-step explanation:

With the information given you can work your way around the table to fill in the blanks

300-120=180 Red-footed one-headed

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6 0
3 years ago
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dezoksy [38]
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3 years ago
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6. Make Sense and Persevere If x represents the number of
IrinaVladis [17]

The difference between the gas prices in 2013 and 2001 is 3.00

<h3>Graphing tool</h3>

See attachment for the graph of the line of best fit

<h3>The equation</h3>

Start by calculating the slope of the line of best fit using:

b = \frac{y_2 -y_1}{x_2 -x_1}

From the line of best fit, we have:

b = \frac{3 -2}{8 -4}

The regression equation is then represented as:

\^y = b(\^x - x_1) + y_1

So, we have:

\^y = \frac 14 (\^x - 4) + 2

\^y = \frac 14\^x - 1 + 2

\^y = \frac 14\^x + 1

So, the linear regression equation is:

\^y = \frac 14\^x + 1

In 2001, the value of x is 1.

So, we have:

\^y_1 = \frac 14\times (1) + 1

\^y_1 = 1.25 \\

In 2013, the value of x is 13.

So, we have:

\^y_2 = \frac 14\times (13) + 1

\^y_2 = 4.25

So, the difference (d) between the prices is:

d = 4.25 - 1.25

d = 3.00

Hence, the difference between the gas prices in 2013 and 2001 is 3.00

Read more about linear regression at:

brainly.com/question/17844286

7 0
3 years ago
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