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disa [49]
3 years ago
12

(x^3+43-49x-7x^2)/(x^2-49)

Mathematics
2 answers:
GaryK [48]3 years ago
7 0
(X-7) is an answer and -300 is the reminder
liraira [26]3 years ago
7 0

Answer:

Quotient = x - 7,

Remainder = -300.

Step-by-step explanation:

Here, the given expression,

\frac{x^3+43-49x-7x^2}{x^2-49}

=\frac{x^3-7x^2-49x+43}{x^2-49}

By the long division ( shown below ), we get,

\frac{x^3-7x^2-49x+43}{x^2-49}=x-7-\frac{300}{x^2-49}

Hence, in the given division problem,

Quotient = x - 7,  

Remainder = -300.

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