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3 years ago

Help please quickly thank you so much

Mathematics

2 answers:

vredina [299]3 years ago

5 0

Answer:

x = 128

Step-by-step explanation:

All angles in any quadrilaterals(any shape with 4 sides) add up to 360. There are two right angles in the trapezoid which represents 90 degrees. We are also given the angle 52 degrees. To find x, we need to add all the values together and subtract from 360. To do this the equation should look like this: 90 + 90 + 52 + x =360. This simplifies to 232 + x = 360. Then we subtract 232 from both sides to find x. x = 128.

STALIN [3.7K]3 years ago

4 0

Answer:

120 deg

Step-by-step explanation:

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Answer:

The student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

Step-by-step explanation:

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$P = 2l + 2w$

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are $\sqrt{50a^3b^2}$ and $\sqrt{200a^3}\:\:$ .

Here is the student's solution:

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

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The student made an error in calculating $30ab\sqrt{2a}+20a\sqrt{2a}$ , because $30ab\sqrt{2a}+20a\sqrt{2a}$ are not like terms.

Hence, $30ab\sqrt{2a}+20a\sqrt{2a}$ can not be simplified to $30ab\sqrt{2a}$

Therefore, the student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

Here is the correct Solution:

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

$=10ab\sqrt{2a}+20a\sqrt{2a}$

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