Answer: [C]: " x³ + 8x² + 11x − 20 " .
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Step-by-step explanation:
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Given: " f(x) = x² + 3x − 4 " ; and
" g(x) = x + 5 " ;
Find: " f(x) ⋅ g(x) " :
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f(x) ⋅ g(x) =
" (x² + 3x − 4) (x + 5) " ;
↔ " (x + 5) (x² + 3x − 4) " ;
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<u>Note</u>: " (a + b) (c + d + e) = ac + ad + ae + bc + bd + ae " ;
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→ " (x + 5) (x² + 3x − 4)
= (x * x²) + (x * 3x) + (x*-4) + (5*x²) + (5*3x) + (5*-4) " ;
= (x³) + (3x²) + (-4x) + (5x²) + (15x) + (-20) ;
= x³ + 3x² − 4x + 5x² + 15x − 20 ;
→ Combine the "like terms" :
+ 3x² + 5x² = + 8x² ;
− 4x + 15x = + 11 x ;
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→ And rewrite:
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→ " x³ + 8x² + 11x − 20 " ;
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→ which is: Answer choice: [C]: " x³ + 8x² + 11x − 20 " .
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Hope this helps!
Best wishes!
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