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2 years ago

Help me please someone

Mathematics

2 answers:

Crazy boy [7]2 years ago

5 0

Same I think so too that it’s c

d1i1m1o1n [39]2 years ago

4 0

The answer for this question is A

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X^2+2x-8=0 in simplest radical form

madreJ [45]

2⃣, -4⃣ = x; no radical necessary.

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2 years ago

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krek1111 [17]

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3 years ago

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Please help for brainliest

solong [7]

Answer:

I think it would be R and S

Step-by-step explanation:

Because if you graph these they make a slope but if you graph T it's just straight line.

7 0

3 years ago

(4x2 - 10x -24) (2x + 3)

jeyben [28]

Answer:

Apply BODMAS

Step-by-step explanation:

PLEASE FIND THE PICTURE BELLOW

SOLUTION STEPS

(4⋅2−10x−24)(2x+3)

Multiply 4 and 2 to get 8.

(8−10x−24)(2x+3)

Subtract 24 from 8 to get −16.

(−16−10x)(2x+3)

Apply the distributive property by multiplying each term of −16−10x by each term of 2x+3.

−32x−48−20x

−30x

Combine −32x and −30x to get −62x.

−62x−48−20x

3 0

2 years ago

$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t

Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $6000 = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $\dfrac{6000}{4000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

Or, $\frac{3}{2}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, 1.5 = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $1.5^{\frac{1}{15}}$ = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 - 1 = $\dfrac{r}{100}$

or, 0.0275 = $\dfrac{r}{100}$

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0

3 years ago