When downloading a large file from the internet Alice interrupted the download by closing her computer. Later that evening she r
1 answer:
Using the slope concept, it is found that the rate of download of the file is of 1920 MB/s.
<h3>What is the slope?</h3>The slope of a linear function is given by the <u>change in the output divided by the change in the input</u>.
In this problem:
- 3 minutes since resuming the download 6720 total MegaBytes (MB).
- 5 minutes since resuming the download 10560 total MegaBytes (MB) of the file had been downloaded..
- Hence, in 2 minutes, there was a change of 10560 - 6720 = 3840 MB, which means that the slope is:
The rate of download of the file is of 1920 MB/s.
You can learn more about the slope concept at brainly.com/question/25934562
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The confidence interval is 
.
We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.
Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.
To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.
The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.
Thus the confidence interval is 77.28 +/ 2.23.
We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.
Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.
To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.
The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.
Thus the confidence interval is 77.28 +/ 2.23.