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barxatty [35]
3 years ago
14

Please help due tomorrow

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0
Tip- download Cymath in the future for problems like this!

D. fill 3/10 for r so
- 4 \frac{4}{9} ( \frac{3}{10} )
-  \frac{36 + 4}{9}  \times  \frac{3}{10}
-  \frac{40}{9}  \times  \frac{3}{10}
-  \frac{120}{90}
-  \frac{4}{3}  \: or \:  - 1 \frac{1}{3}

E. fill -2(2/3) for W
- 3 \frac{1}{8} ( - 2 \frac{2}{3} )
\frac{ - 24 + 1}{8}  \times  \frac{ - (6 + 2)}{3}
- \frac{25}{8}  \times  \frac{ - 8}{3}
-  \frac{ - 200}{24}
\frac{25}{3}  \: or \: 8 \frac{1}{3}
F. fill (-3/4)
((\frac{3}{8} )( \frac{ - 3}{4} )) + (( \frac{1}{8} )( \frac{ - 3}{4} ))
\frac{3  \times   - 3}{8 \times 4} +  \frac{1 \times  - 3}{8 \times 4}
- \frac{9}{32}   -  \frac{3}{32}
- \frac{12}{32}  =   - \frac{3}{8}











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Answer:

The y-intercept is (0,1).  The x values at the horiz. intercepts are:

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Step-by-step explanation:

It'd be helpful to rewrite f(x) = 3-x2+3x-2 with the powers of x in descending order and using " ^ " to denote exponentiation:

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x-intercepts:  let y = f(x) = 0 = -x^2 + 3x + 1.  Let's use the quadratic formula with a = -1, b = 3 and c = 1 to determine the roots of this polynomial.  The discriminant, b^2-4ac, is 9-4(1)(1), or 5.

Thus, there are two real, unequal roots.  They are:

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x =  ---------------------------------

                     2


or { (-3+√5)/2, (-3-√5)/2 }

These are your two horizontal intercepts, where the function is zero.

Because the coefficient -1 of the x^2 term is negative, the parabola representing this function opens down.

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