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3 years ago

X + 2x - 9 + xy - 2 - 3x + 2xy - 4

Mathematics

1 answer:

frozen [14]3 years ago

3 0

Answer:

3xy-15 thats the simplified form

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One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$

$\sqrt {202 \ cm^{2} }=c$

$14.2126704036 \ cm =c$

We are told to round to the nearest tenth.

14.2126704036

The 1 in the hundredth place tells us to leave the 2 in the tenth place.

$14.2 \ cm= c$

The hypotenuse is equal to 14.2 centimeters.

3 0

3 years ago

Factor the expression using the GCF. 100 – 80

DochEvi [55]

Answer:

The Greatest Common Factor (GCF) for 100 and 80, notation GCF (100,80), is 20.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is -3.2 + (1 1/2) + (-2)

CaHeK987 [17]

Answer:

-3.7

Step-by-step explanation:

-3.2 + 1.5 -2 = -3.7

6 0

3 years ago

Read 2 more answers

M1 Matrix is:

harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix $M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)$

The Inverse of a 2X2 matrix

$A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)$

can be found using the following:

$A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)$

Therefore:

$M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)$

Next, we find the product $M^{-1}M$

$M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)$

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0

3 years ago

Please please help asap <3

sasho [114]

Answer:

3to-9

Step-by-step explanation:

that what I know and I think so

8 0

3 years ago