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natita [175]
3 years ago
10

What is 7x^5-33x^4-4x^2+3x+52=0

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
7x^5-33x^4-4x^2+3x+52=

ANSWER: 7x^5 -33x^4 -4x^2+3x+52  (because there are no like terms)
                  
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4 times x with an exponent of 2 plus 2 times y with an exponent of 4. X=-3 y=2
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Answer:

Step-by-step explanation:

Your equation is: 4*x^{2} +2 * y^{4}

You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

4*(-3)^{2} +2 * 2^{4}

First, you want to do the exponentiation (meaning you want to calculate (-3)^{2} and 2^{4} parts). (-3)^{2} equals 9 and 2^{4} equals 16.

So the equation now is:

4*9+2*16

Now you want to do multiplication. 4*9 equals 36 and 2*16 equals 32. So you're left with:

36+32

Which equals 68.

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