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natita [175]
3 years ago
10

What is 7x^5-33x^4-4x^2+3x+52=0

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
7x^5-33x^4-4x^2+3x+52=

ANSWER: 7x^5 -33x^4 -4x^2+3x+52  (because there are no like terms)
                  
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Evaluate g(x)=3x when x=−2,0, and 5.<br><br> g(−2)= <br><br> g(0)= <br><br> g(5)=
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Answer:

g(-2)= -6, g(0)=0, g(5)=15

Step-by-step explanation:

Plug in each value of x into the function g(x) aka 3(x).

Multiply by three.

4 0
3 years ago
F(x)=24x+7 What is the domain of f
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The domain of f(x) = 24x + 7 is all real numbers except where the expression is undefined. in this case, there is no real number that makes the expression undefined. 

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7 0
3 years ago
the left and right page numbers of an open book are two consecutive integers whose sum is 589. find these page numbers
kramer

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Step-by-step explanation:

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3 years ago
Find the area of the shape shown below. I reallly need help and do not put a unbelieable answer.
larisa [96]

Answer:

63/2 or 31.5

Step-by-step explanation:

we can split this shape into 2, a triangle and a rectangle

A triangle = bh/2 = 7*3*1/2 = 21/2

A rectangle = b*h = 3*7 = 21

21/2 + 21 = 63/2

3 0
3 years ago
On a certain hot​ summer's day, 477 people used the public swimming pool. The daily prices are 1.50 for children and 2.25 for ad
Akimi4 [234]

Answer:

212 children, and 265 adults

Step-by-step explanation:

To find the number of children and adults, we can set up a systems of equations.

x= number of children

y= number of adults

Equation 1: Price

1.50x+2.25y=914.25

Equation 2: Total number of people

x+y=477

Now, let's solve the equation using substitution.

Rearrange the second equation to solve for one variable.

x+y=477

x=477-y

Now plug x equals into the first equation, and solve for y.

1.50x+2.25y=914.25

1.50(477-y)+2.25y=914.25

715.5-1.50y+2.25y=914.25

715.5+0.75y=914.25

0.75y=198.75

y=265

We just solved for the number of adults. Now let's plug y equals into the second equation to find the number of children.

x+y=477

x+265=477

x=212

7 0
2 years ago
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