Answer:
A
Step-by-step explanation:
To write the equation, find the slope of the line using the two points. Find the difference in y values over the difference in x values.
Write the equation using the slope m=3/2 and the point slope form.
This is the equation of the line. You can convert it to slope intercept form:
Answer:
42
Step-by-step explanation:
a = 2, b = 5, and c = 1
- a*(4b + c²) = ⇒ plug in values
- 2*(4*5 + 1²) = ⇒ solving exponents
- 2*(20 + 1) = ⇒ parenthesis
- 2*21 = ⇒ multiplication
- 42 ⇒ answer
Answer:
D. x = 7
Step-by-step explanation:
NOTE : <u><em>there should be an equal sign somewhere in the given expression.</em></u>
suppose the equation is the following:
3(x-4)-5 = x-3
………………………………………………………
3(x - 4) - 5 = x - 3
⇔ 3x - 12 - 5 = x - 3
⇔ 3x - 17 = x - 3
⇔ 3x - 17 + 17= x - 3 + 17
⇔ 3x = x + 14
⇔ 2x = 14
⇔ x = 14/2
⇔ x = 7
Hi,
There are no other simple steps to reduce the square root of one hundred and sixty-three.
The actual square root value is ≈12.767145334803704
But we have taken only significant figures and it is as 12.76.
Hope it helps! :)
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
