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MAVERICK [17]
3 years ago
13

Find the discount if the original price is $8.05 and the percent markdown is 10 % round to the nearest cent

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0
Well if 100%= $8.05
then to find 10% you divide by 100.
10%=$0.85
You would then take this off of your original price. This is how I like to lay mine out:

  100%=$8.05
-   10%=$0.85
=   90%=$7.20

Therefore 90% of $8.05 is $7.20
Alecsey [184]3 years ago
4 0
The answer is : Discount is $ 7.25.
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Which equation represents the line that is perpendicular to and passes through (-40,20)?
emmasim [6.3K]

The equation of the perpendicular line to the given line is: y = -5/4x - 30.

<h3>What is the Equation of Perpendicular Lines?</h3>

The slope values of two perpendicular lines are negative reciprocal of each other.

Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.

Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.

Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:

20 = -5/4(-40) + b

20 = 50 + b

20 - 50 = b

b = -30

Substitute m = -5/4 and b = -30 into y = mx + b:

y = -5/4x - 30

The equation of the perpendicular line is: y = -5/4x - 30.

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1 year ago
Find The Value Of The Following
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2. (-1) 3. (-3.75)

Step-by-step explanation:

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3 years ago
According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at
miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

np=80*0.1=8

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that  the percentage is lower in this district.

Then, the null and alternative hypothesis are:

H_0: \pi=0.173\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.057) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that  the percentage is lower in this district.

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