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Sloan [31]
4 years ago
8

What is the percent 5.89966

Mathematics
2 answers:
Naddik [55]4 years ago
8 0
The correct answer would be 589.966% because you have to do 5.89966 multiplied by 100 which then gives you the answer of 589.996%
Lorico [155]4 years ago
4 0
The answer is 5.9% I think because you have to round up if it’s 5 and above
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3 years ago
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Follow the rules of PEMDAS:

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Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i
bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1)  with respective to 'x'

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differentiating equation (2)  with respective to 'y'

\frac{dy}{dt} = -sint

The length of curve is

\int\limits^\pi_\pi  {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt

\int\limits^\pi_\pi  \,   {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

\int\limits^\pi_\pi  \,   {\sqrt{(2+2cost } } \, dt

\sqrt{2} \int\limits^\pi_\pi  \,   {\sqrt{(1+1cost } } \, dt

again using formula, 1+cost = 2cos^2(t/2)

\sqrt{2} \int\limits^\pi _\pi  {\sqrt{2cos^2\frac{t}{2} } } \, dt

Taking common \sqrt{2} we get ,

\sqrt{2}\sqrt{2}  \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt

2(\int\limits^\pi _\pi  {cos\frac{t}{2} } \, dt

2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }

length of curve = 4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

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