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Mice21 [21]
3 years ago
5

The measurement of the complement of an angle exceeds the measure of the angle by 25%. Find the measurement of the angle and its

complement.
Mathematics
1 answer:
tester [92]3 years ago
3 0
Let the angles be A and C 

<span>Complimentary angles, therefor </span>
<span>A + C = 90 </span>

<span>The measurement of the complement of an angle exceeds the measure of the angle by 25% (you used a % sign so I'll use % instead of degrees) </span>
<span>C = 1.25A </span>

<span>Substitute </span>
<span>A + 1.25A = 90 </span>
<span>2.25A = 90 </span>
<span>A = 40º <----- </span>
<span>C = 50º <----- </span>
<span>------------------------------ </span>

<span>If you meant 25º </span>
<span>A + (A + 25) = 90 </span>
<span>2A + 25 = 90 </span>
<span>2A = 65 </span>
<span>A = 32.5º </span>
<span>C = 57.5º</span>
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3 years ago
What is the length of the missing leg?
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Answer:

a=\sqrt{609}\\\\a\approx 24.67793

Step-by-step explanation:

To solve for the leg of the missing right triangle, one must use the Pythagorean theorem. The Pythagorean theorem states the following,

a^2+b^2=c^2

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a^2+b^2=c^2\\

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8 0
2 years ago
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FIND THE PERCENT DECREASE FROM 20 TO 17. round to nearest tenth if necessary.<br><br> give formula
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Answer:

The percentage decrease is 15%.

Step-by-step explanation:

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So in this case:

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3 years ago
What is the GCF of (8x-6) <br><br>sos T-T
makvit [3.9K]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the G.C.F. of 8x-6.

\triangle~\fbox{\bf{KEY:}}

  • G.C.F. stands for Greatest Common Factor.

So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:

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So the GCF is:

2

Now, we can also factor it out by placing it outside the parentheses ():

2(4x-3)

See, we factored it out by dividing both terms of the expression by the G.C.F.

\ddot\bigstar Remember this...

\fbox{\bf{We\;factor\;out\;the\;G.C.F.\;by\;dividing\;all\;the\;terms\;of\;the\;expression\;by\;it}}

Hope this helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students :)

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