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3 years ago

Help me pleaseee, will mark the Brainliest !

Mathematics

2 answers:

Sidana [21]3 years ago

8 0

Answer:96ft explanation;

snow_lady [41]3 years ago

6 0

Answer:

Step-by-step explanation:

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An angle measured 34 degrees less than the measure of a complementary angle. What is the measure of each angle?

Tanzania [10]

107 for the smaller angle or 73 if its two separate angles

4 0

3 years ago

John was traveling 1700 feet in 20 seconds. How fast was the car going in miles per hour

bagirrra123 [75]

Answer:

612000

Step-by-step explanation:

(20*3)*60=360

360*1700=612000

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

How to solve this brainteaser

laila [671]

Answer:

last row equals 333

Step-by-step explanation:

The clock showing time 9:00 should be worth 9 points, and the clock showing 3:00 should be worth 3 points, giving for the first row:

9 + 9 + 3 = 21

the three equal calculators showing 1234 are worth 10 points each:

1+2+3+4 = 10

and 10 + 10 + 10 = 30

the light bulbs should be 15 points each then giving 15 + 15 - 15 = 130 - 15 = 15 Notice also that they all have 5 rays of light coming out (so a 3 points per ray)

Now for the bottom line we have:

9 + (1+2+2+4) times 3 * 12 (only four rays on each bulb thus 4 * 3 = 12)

Notice we added the figures that appear in the calculator.

9 + 9 * 36 = 333

7 0

3 years ago

Need help w precal/algebra 2

Daniel [21]

Answer:

g(-2) = -7

Step-by-step explanation:

To find g(-2), plug -2 into g(x).

g(x) = -4x² + 3x + 15

g(-2) = -4(-2)² + 3(-2) + 15

g(-2) = -4(4) + 3(-2) + 15

g(-2) = -16 + (-6) + 15

g(-2) = -1 + (-6)

g(-2) = -7

3 0

3 years ago