2x+21=4x+21-2x is solution or no

Mathematics

2 answers:

Lapatulllka [165]4 years ago

4 0

A solution is an answer to a math question, so no this is not a solution

Elena L [17]4 years ago

3 0

I got x is 0. No solution

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Your credit card has a balance of $3300 and an annual interest rate of 14%. You decided to pay off the balance over two years. I

NARA [144]

9514 1404 393

Answer:

$137.90 more each month
$246.00 less total interest

Step-by-step explanation:

The amortization formula is ...

A = P(r/12)/(1 -(1 +r/12)^(-12t))

for the monthly payment on principal P at annual rate r for t years. Here, we have P=3300, r = 0.14, and t=1, so the monthly payment is ...

A = $3300(0.14/12)/(1 -(1 +0.14/12)^-12) ≈ $296.30

The payment of $296.30 is ...

$295.30 -158.40 = $137.90 . . . more each month

The total amount paid is 12×$296.30 = $3555.60, so 255.60 in interest. This amount is ...

$501.60 -255.60 = $246.00 . . . less total interest

3 0

3 years ago

Can you help me please

kicyunya [14]

9514 1404 393

Answer:

domain: x ∉ {-4, 3}
range: y ∉ {1}
horizontal asymptote: y=1
vertical asymptote: x=3

Step-by-step explanation:

The expression reduces to ...

$\dfrac{x^2+9x+20}{x^2+x-12}=\dfrac{(x+4)(x+5)}{(x+4)(x-3)}=\dfrac{x+5}{x-3}\quad (x\ne-4)$

The domain is limited to values of x where the expression is defined. It is undefined where the denominator is zero, at x=-4 and x=3. The graph of the expression has a "hole" at x=4, where the numerator and denominator factors cancel.

the domain is all real numbers except -4 and +3

The function approaches the value of 1 as x gets large in magnitude, but it cannot take on the value of 1.

the range is all real numbers except 1

As discussed in 'range', there is a horizontal asymptote at y=1. That is the value you would get if you were to determine the quotient of the division:*

(x+5)/(x-3) = 1 + (8/(x-3)) . . . . quotient is 1

There is a vertical asymptote at the place where the denominator is zero in the simplified expression: x = 3.

vertical asymptote at x=3; horizontal asymptote at y=1

_____

* For some rational functions, the numerator has a higher degree than the denominator. In those cases, the quotient may be some function of x. The "end behavior" of the expression will match that function. (Sometimes it is a "slant asymptote", sometimes a higher-degree polynomial.)