Answer:
1.c
2.A
3.E
4.B
5.D
Step-by-step explanation:
hope my answer are correct .
4,700 is one of the correct answers to this question.
Pre Image having vertices : △ABC with vertices A(−5, −4), B(−7, 3), C(3, −2)
Image having vertices : △A′B′C′ with vertices A′(−3.75, −3), B′(−5.25, 2.25), C′(2.25, −1.5).
As, Size of Preimage > Size of image
So, 0<Dilation Factor <1
When a triangle is dilated , the preimage and image are similar to each other .
Scale factor can be get through by finding the ratio of any of corresponding sides of triangle.
So, Scale Factor of Dilation = 
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
