Answer:
length x and width x-2
perimeter of rectangle=2[l+b]=2[(x-2)+x]=4x-4 is your answer
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
Answer:
3
Step-by-step explanation:
You know that angle Y is a right angle because XY is the radius and YZ is a tangent to the circle. So, you can use the pythagorean theorem to find the third side:
XY^2+4^2=5^2
XY^2+16=25
XY^2=9
XY=3
Hope this was helpful! :)
Answer:
The measure of angle LMN is 68° ⇒ the last answer
Step-by-step explanation:
* Lets revise the properties of the rhombus
- The rhombus has 4 equal sides in length
- Every two opposite angles are equal in measure
- Every two adjacent angles are supplementary (their sum = 180°)
- The two diagonals bisect each other
- The two diagonals perpendicular to each other
- The two diagonals bisect the vertices angles
* Lets solve the problem
∵ LMNO is a rhombus
∴ ∠LMN and ∠MNO are adjacent angles
∴ ∠LMN and ∠MNO are supplementary
∴ m∠LMN + ∠MNO = 180°
∵ m∠MNO = 112°
∴ m∠LMN + 112° = 180° ⇒ subtract 112 from both sides
∴ m∠LMN = 68°
* The measure of angle LMN is 68°
