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makkiz [27]
3 years ago
6

Triangle ABCTriangle ABC ​is transformed with the center of dilation at the origin. Pre-image: △ABC with vertices A(−5, −4), B(−

7, 3), C(3, −2) Image: △A′B′C′ with vertices A′(−3.75, −3), B′(−5.25, 2.25), C′(2.25, −1.5) What is the scale factor of the dilation that maps the pre-image to the image?

Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Pre Image  having vertices : △ABC with vertices A(−5, −4), B(−7, 3), C(3, −2)

Image having vertices : △A′B′C′ with vertices A′(−3.75, −3), B′(−5.25, 2.25), C′(2.25, −1.5).

As, Size of Preimage > Size of image

So, 0<Dilation Factor <1

When a triangle is dilated , the preimage and image are similar to each other .

Scale factor can be get through by finding the ratio of any of corresponding sides of triangle.

\frac{A'B'}{AB}=\frac{\sqrt{2.25 +27.5625}}{\sqrt{4+49}}=\sqrt{\frac{29.8125}{53}}=\sqrt{0.5625}=0.75=\frac{3}{4}

So, Scale Factor of Dilation = \frac{3}{4}=0.75

gavmur [86]3 years ago
4 0

Answer:

3/4 = 0.75

Step-by-step explanation:

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There is a lightning rod on top of a building. From a location 500 feet from the base of the building, the angle of elevation to
Kitty [74]
<h2>Hello!</h2>

The answer is:

The height of the  lightning rod is 27.4 feet.

<h2>Why?</h2>

To solve the problem, we need to use the given information about the two points of observation, since both are related (both finish and start at the same horizontal distance) we need to write to equations in order to establish a relationship.

So, writing the equations we have:

We know that the angle of elevation from the base of the buildings is 36°

Also, we know that from the same location, the angle of elevation to the top of the lightning rod is 38°.

Using the information we have:

To the top of the building:

tan(\alpha )=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}

To the top of the lightning rod:

tan(\alpha )=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}

Now, isolating we have:

tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\DistanceToTheTopOfTheBuilding=tan(36\°)*BuildingBase \\\\DistanceToTheTopOfTheBuilding=tan(36\°)*500feet=363.27feet

Also, we have that:

tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*BuildingBase\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*500feet=390.64feet

Therefore, if we want to calculate the height of the lightning rod, we need to do the following:

Let "x" the distance to the top of the building and "y" the distance to the top of the lightning rod, so:

LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet

Rounding to the nearest foot, we have:

LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet=27.4feet

Hence, the answer is:

The height of the lightning rod is 27.4 feet.

Have a nice day!

5 0
3 years ago
Round your answer to the nearest hundreth. ​
katovenus [111]

Answer:

78.54 is the radius of a circle of 5 inches

Step-by-step explanation:

the formula of the area of a circle is

A = πr^2

When you multiply 5 times 5, you get 25. Then, multiply 25 by pi to recieve 78.54 rounded to the nearest hundredth.

4 0
2 years ago
Given: AB tangent at D, AD = OD = 4 Find: Area of the shaded region
MrMuchimi

Answer:

1.72

Step-by-step explanation:

AB tangent at D, AD = OD = 4

so triangle OAD is right angle with side of 4 and 4.

area of OAD = 1/2 * 4 * 4 = 8

Angle AOD = DAO = 45 deg.

so circular sector OCD area = area of circle O * 45/360

= pi * 4 * 4 * 45/360

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Shade area ACD = trigangle OAD - circular sector OCD

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4 0
3 years ago
For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation o
riadik2000 [5.3K]

Answer: The length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.

Step-by-step explanation:

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Given : For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation of 5 days.

According to the Empirical Rule, the length of approximately 68% of all pig pregnancies will fall between 114-1(5) days  and 114+1(5) days .

i.e. the length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.

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Her profit was 126$ because she spent 24$ on her materials and then charged 5$ per 2 so you get 150$ then subtract the 24
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