Answer:
B
Step-by-step explanation:
I got 100 on my test and that was my answer
Plug it into the distance formula.
d= (sqrt) (x2-x1)^2 +(y2-y1)^2
d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54
The distance is 54 units.
I hope this helps!
~kaikers
J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
Step-by-step explanation:
The equation of line A:
y-1=0, 5x-3
y=0, 5x-2. Hence its gradient is 0,5
For line B, its you intercept is -8, so y=mx-8.
When x = -4, y=-4m -8 =0 as shown in the graph. This means that m = -2.
Since |-2| > |0, 5|, line B is steeper than line A.