3 years ago

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Mathematics

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Svetllana [295]3 years ago

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(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

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Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

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Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

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The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

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