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Naily [24]
3 years ago
10

Stuck on this question. Help appreciated!!

Mathematics
1 answer:
marta [7]3 years ago
4 0

Answer:

the missing is 4.98

Step-by-step explanation:

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A triangular prism is 19 centimeters long. It has a triangular face with a height of 14 centimeters. The volume of the prism is
andreyandreev [35.5K]

The base of its triangular face of the triangular prism is found as 17.7 cm.

<h3>What is defined as the triangular prism?</h3>
  • A polyhedron with two triangular bases as well as three rectangular sides is known as a triangular prism.
  • It is a three-dimensional shape with three side faces but also two base faces that are connected by the edges.

The formula for the volume of triangular prism is;

Volume = base area x length

The base area of the triangular base.

The area of the triangle = 1/2 base×height

The given values are-

  • volume = 2,354. 1 cubic centimeters.
  • length = 19 cm
  • height = 14 cm.

Thus, volume = base area x length

volume =  1/2 base × height × length

base = 2v/(height × length)

Put the values;

base = 2×2,354.1/(14 × 19)

base = 4708.2/(14 × 19)

base = 17.7 cm

Thus, the base of the triangular  prism is found as 17.7 cm.

To know more about the triangular prism, here

brainly.com/question/16128664

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7 0
1 year ago
If tam walks 2 miles to school during gym and runs 3 times as fast as Dante how many miles would Dante go if he ran 1 mile
zalisa [80]
Dante would still go 1 mile, because you provided the answer in the problem.
3 0
4 years ago
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Find the area of the parallelogram.
Nadya [2.5K]
It’s d cuz it has 14 of them
6 0
4 years ago
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What is the image of (9,0) after a dilation by a scale factor of 2 centered at the origin?
Advocard [28]
(5,7). Because the origin centers 2 by dilation.
6 0
3 years ago
Hello.
melisa1 [442]

Answer:

\large{\boxed{\sf 2y^2\sqrt{2y}}}

Step-by-step explanation:

Here the given expression to us is ;

\sf\qquad\longrightarrow \dfrac{\sqrt{64xy^5}}{\sqrt{8x}}

Recall that ,

\sf\qquad\longrightarrow \dfrac{\sqrt{x}}{\sqrt{y}}=\sqrt{\dfrac{x}{y}}

On using this , we have ;

\sf\qquad\longrightarrow \sqrt{\dfrac{\cancel{64}\cancel{x}y^5}{\cancel{8x}}}

Simplify ,

\sf\qquad\longrightarrow \sqrt{ 8 y^5}

The prime factorisation of 8 is 2³ . So ;

\sf\qquad\longrightarrow \sqrt{ (2^3)(y^5)} =\sqrt{(2^2)(2)(y^2)(y^2)(y)}

Simplify the square root ,

\sf\qquad\longrightarrow \pink{ 2y^2\sqrt{2y}}

<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>e</u><u>q</u><u>u</u><u>i</u><u>r</u><u>e</u><u>d</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>i</u><u>s</u><u> </u><u>2</u><u>y</u><u>²</u><u>√</u><u>{</u><u>2</u><u>y</u><u>}</u><u> </u><u>.</u>

6 0
3 years ago
Read 2 more answers
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