The answer is C <<<=====
It can't be anything else. It is not a right angle. A>90
It can't be acute because one angle is greater than 90.
It can't scalene because at least 2 of the angles (and 2 sides) are equal.

8 0

3 years ago

What is the solution set of x2 + 5x + 1 = 0?

DerKrebs [107]

Answer:

$\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}$

Step-by-step explanation:

$x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}$

3 0

3 years ago

The first steps in writing f(x) = 3x^2 -24x+10 in vertex form what is the function written in vertex form

Vika [28.1K]

F(x) = 3(x-4)^2-38 because finding the perfect square would get you f(x)+38=3(x^2-8x+16) and then finding the squareroot of that and moving the constant on the left back to the right would leave u with f(x)=3(x-4)^2-38

4 0

3 years ago

Read 2 more answers

Find the area of each triangle o the nearest tenth.

blagie [28]

Answer:

A is , 18.1058 B is , 24.91575

Step-by-step explanation:

6 0

2 years ago