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FinnZ [79.3K]
3 years ago
7

If a circle has a circumference of C, what is the area of the circle in terms of C? A. A=πC

Mathematics
1 answer:
mart [117]3 years ago
5 0
The area of the circle is expressed in the formula A = pi r^2 while the formula of getting the circumference of the circle is C = 2pi *r. Trying to express A in terms of C, we square C first into C2 = 4pi^2r^2.  In this case, the answer to this problem therefore is A = C^2/4 pi. Answer is B
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If k-9=5(k-3)find k​
jok3333 [9.3K]

Answer:

K = 3/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

k−9=5(k−3)

k+−9=(5)(k)+(5)(−3)(Distribute)

k+−9=5k+−15

k−9=5k−15

Step 2: Subtract 5k from both sides.

k−9−5k=5k−15−5k

−4k−9=−15

Step 3: Add 9 to both sides.

−4k−9+9=−15+9

−4k=−6

Step 4: Divide both sides by -4.

-4k/-4 = -6/-4

K = 3/2

7 0
3 years ago
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2 years ago
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Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
Does all rhombuses have 2 pairs of parallel sides?
attashe74 [19]
Yes, all of the rhombuses have 2 pairs of parallel side.





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3 years ago
Question 1
Arada [10]
The answer is n+7 and 7+n
5 0
3 years ago
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