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ikadub [295]
3 years ago
10

Which ordered pair is a solution for 3x + 4y < 12?

Mathematics
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

D, (1,2)

Step-by-step explanation:

It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).

1. Plug in your x value (1 in this circumstance) and solve:

3(1) + 4y < 12

3 + 4y < 12

2. Plug in your y value (2 in this circumstance) and solve:

3 + 4(2) < 12

3 + 8 < 12

3. Solve

3 + 8 = 11

11 < 12

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If I Had A Hammer Hardware has sales of $5000 in its first month. Suppose sales were to increase by 4% every month. In how many
mixer [17]

After 14 months after the first month would the sales reach $9000

For given question,

A Hammer Hardware has sales of $5000 in its first month.

The sales were to increase by 4% every month.

We need to find the number of months after the first month would the sales reach $9000

Let the exponential function for sales is,

f(n)= a (1 + r)^{n}

where, n is the number of months

a is the sales of the first month

r is the rate of increment

So, a = $5000, r = 0.04, f(n) = $9000

Substitute values in above equation.

⇒ 9000 = 5000 × (1 + 0.04)^{n}

Solve above equation for n.

⇒ 1.8 = (1.04)^n

⇒ n = log_{1.04}^{(1.8)}

⇒ n = 14.9

⇒ n ≈ 15

Therefore, after 14 months after the first month would the sales reach $9000

Learn more about the exponential growth here:

brainly.com/question/11487261

#SPJ4

3 0
1 year ago
For a two way frequency tables the variables can be found
34kurt

Answer: C. Along the rows and columns .

Step-by-step explanation:

3 0
4 years ago
From 85 books to 150
Lostsunrise [7]
I'm not sure what the question is but I think your asking 150-85=65
8 0
4 years ago
(solve for x ) −28−1/5n=3/5n
almond37 [142]

Answer:

- 28 -  \frac{1}{5} n =  \frac{3}{5} n \\  - 28 =  \frac{1}{5} n +  \frac{3}{5} n \\  - 28 =  \frac{4}{5} n \\ n =  \frac{( - 28) \times 5}{4}  \\ n = ( - 7) \times 5 \\ \boxed{ n =  - 35}

  • <u>n=-35</u> is the right answer.

4 0
3 years ago
in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation o
Alinara [238K]

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

z = \dfrac{x - \mu }{\sigma}

z = \dfrac{x - 170000 }{16500}

Now;

P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})

P( Z < \dfrac{T- 170000}{16500})< 0.02

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

\dfrac{T- 170000}{16500}

{T- 170000}

{T- 170000}< - 33990

{T}< - 33990+ 170000

{T}

Thus; the guarantee period should be less than 136010 miles

4 0
4 years ago
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