All categories

2 years ago

Which ordered pair is a solution for 3x + 4y < 12?

Mathematics

1 answer:

Andre45 [30]2 years ago

5 0

Answer:

D, (1,2)

Step-by-step explanation:

It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).

1. Plug in your x value (1 in this circumstance) and solve:

3(1) + 4y < 12

3 + 4y < 12

2. Plug in your y value (2 in this circumstance) and solve:

3 + 4(2) < 12

3 + 8 < 12

3. Solve

3 + 8 = 11

11 < 12

You might be interested in

Write the numbers in order from least to greatest. -7, -6.5, -6.2, 0, -4.5

algol13

Answer: -7, -6.5, -6.2, -4.5, 0

I hope this helps, stay safe, and have a great rest of your day. :)

7 0

3 years ago

Read 2 more answers

F(x) = -1<br> g(x) = x-4<br> Can you evaluate (gof)(o)? Explain why or why<br> not.

ella [17]

Answer: Yes. (gof)(0) = -5

(gof)(0) means you will find the function of g(f(0)), which means we will find f(0) and plug that value in for x in the function g(x)

We know f(0) is -1, so we can plug -1 into the equation of g(x)

(gof)(0) = (-1) - 4
(gof)(0) = -5

7 0

3 years ago

Convert repeating decimal to fractions

timurjin [86]

Answer: 8/9

Step-by-step explanation: 0.888... can be simplified to 8/9.

6 0

3 years ago

Hi ik no one would have any hope in my friend basically he got super sick .. and he said nothing would make him feel happier if

nalin [4]

Answer:

Give your friend our best and hope they get better.

Step-by-step explanation:

3 0

2 years ago

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard dev

Nesterboy [21]

Answer:

There is a 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard deviation of 2.1-cm. This means that $\mu = 201.9, \sigma = 2.1$ .

For shipment, 9 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

By the Central Limit Theorem, since we are using the mean of the sample, we have to use the standard deviation of the sample in the Z formula. That is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{9}} = 0.7$

This probability is 1 subtracted by the pvalue of Z when $X = 204.1$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{204.1 - 201.9}{0.7}$

$Z = 3.14$

$Z = 3.14$ has a pvalue of 0.9992. This means that there is a 1-0.9992 = 0.0008 = 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

3 0

3 years ago