The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

----------------(from equation 1)
----------------(given p=58 inches)




----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.





as,
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer:
Step-by-step explanation:
a^-4 x 8^14
the solution is C
Answer:
7
Step-by-step explanation:
We want to evaluate the fraction below for x = 3. We will put the value of x to be 3:

The answer is 7.
Answer: -13, -15
Step-by-step explanation:
If x is the smallest integer, then:
x + (x + 1) + (x + 2) = x - 27
3x + 3 = x - 27
2x = -30
x = -15
Integers: -15, -14, -13
4 / (1/4 - 5/2)
4 / (1/4 -10/4)
4 / (-9/4)
4 x (-4/9) = -16/9