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dezoksy [38]
3 years ago
13

Which of the following is a consumer durable? (1 point)

Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
Answer: D



Explanation: I had this answer on my quiz
Sphinxa [80]3 years ago
6 0

Answer:

C. Car

Step-by-step explanation

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DochEvi [55]

I think that can help for now

7 0
3 years ago
Y-intercept oftheparabola y = x2 – 2x – 3
inessss [21]
(X-3)(X+1)=0
X-3=0
X=3
X+1=0
X=-1
6 0
3 years ago
The population of a town increased from 3450 in 2006 to 4650 in 2011. Find the absolute and relative (percent) increase.
netineya [11]

Answer:

15% increase per year.

Step-by-step explanation:

5,600 - 3,500 = 2,100

2,100 is what percent of 3,500?

2,100 = X*3,500

X =  2,100 / 3,500

X = .60 or 60%

An average of 15% increase per year.

4 0
3 years ago
If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y
zaharov [31]
We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
6 0
3 years ago
At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

C. \frac{504}{48} =10.5

D. \frac{560}{56} =10

E. \frac{315}{30} =10.5

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0
3 years ago
Read 2 more answers
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