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3 years ago

What is the value of (4 minus 2) cubed minus 3 times 4? Negative 20 Negative 4 4 20

Mathematics

2 answers:

Mamont248 [21]3 years ago

6 0

Answer:

-4

Step-by-step explanation:

(4-2)^3 - 3*4

PEMDAS

P arentheses

(2)^3 - 3*4

E xponents

8 -3*4

MD multiply and divide from left to right

8 - 12

AS add and subtract from left to right

-4

trasher [3.6K]3 years ago

5 0

Answer:

-4

Step-by-step explanation:

When solving an expression, use PEMDAS!

4-2 = 2

2^3 (Cubed means to the 3rd) = 8

3 x 4

8-12 = -4

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What is 341/1000 in words

vladimir1956 [14]

Three-forty one over one thousand XD

7 0

3 years ago

A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the

Rina8888 [55]

Answer:

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

Step-by-step explanation:

This problem involves two unknowns:

wind speed, and
speed of the plane in still air.

Let the speed of the wind be $x \rm \; km \cdot h^{-1}$ , and the speed of the plane in still air be $y\rm \; km \cdot h^{-1}$ . It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

It takes the plane three hours to travel $\rm 960\; km$ from Ottawa to with a tail wind (that is: at a ground speed of $x + y$ .)
It takes the plane four hours to travel $\rm 960\; km$ from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of $-x + y$ .)

Create a two-by-two system out of these two equations:

$\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right.$ .

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

$\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

$\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only $1 \times 960$ on the right-hand side. In comparison, adding them will give $7 \times 960$ , which is much more complex to evaluate. Subtracting the second equation ( $3 \times (2)$ ) from the first ( $4 \times (1)$ ) will give the equation

$(12 - (-12) x = 1 \times 960$ .

$24 x = 960$ .

$x = 40$ .

Substitute $x$ back into either equation $(1)$ or $(2)$ of the original system. Solve for $y$ to obtain $y = 320$ .

In other words,

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

3 0

3 years ago

Read 2 more answers

Please solve and show the steps. 2/3z +3 =7

USPshnik [31]

Subtract 3 from both sides:

2/3z=4

divide by 2/3 on both sides (multiple 3/2 on both sides)

z= 6

4 0

2 years ago

Read 2 more answers

I’m so confused. Need the help

fomenos

1.621 kN

Step-by-step explanation:

Let the centerline of the canal be the x-axis. Because the forces exerted by the horses are symmetric to the centerline, only the x-components of these forces contribute to the resultant force on the barge, i.e., the y-components cancel out. Each x-component is equal to $F_x = 839\cos 15$ = 810.4 N. Therefore, the resultant force on the barge is twice this:

$F_{net} = 2(839\:\text{N})\cos 15 = 1620.8\:\text{N}$

$= 1.621\:\text{kN}$

6 0

2 years ago

Three pieces of wood measure 20 cm, 41 cm, 44 cm. If the same amount is cut off each piece, the remaining length can be formed i

SIZIF [17.4K]

The length that can be cut off from the three given pieces of wood equally to form a right triangle is 5 cm

Given parameters:

dimension of the three pieces of wood = 20 cm, 41 cm and 44 cm

To find:

the length that is cut off to form a right triangle

let the length that is cut off from each of the wood = y

From Pythagoras theorem, we will have the following equation.

$(44-y)^2 = (20-y)^2 + (41-y)^2\\\\expand \ the \ equation \ as \ follows;\\\\1936 - 88y + y^2 = 400 - 40y + y^2 + 1681 - 82y + y^2\\\\simplify \ by \ collecting \ similar \ terms \ together\\\\(1936 - 400- 1681) + (-88y + 40y+ 82y) + (y^2 - 2y^2) = 0\\\\-145 +34y - y^2 = 0\\\\multiply \ through \ by \ (-1)\\\\y^2-34y + 145 = 0\\\\factorize \ the \ above \ quadratic\ equation\\\\y^2 -5y - 29y + 145 = 0\\\\y(y - 5) -29(y - 5)=0 \\\\(y -5)(y-29) = 0\\\\y = 5 \ \ \ or \ \ \ \ y = 29$

Since the least measurement of one of the pieces of the wood is 20 cm, we cannot cut off 29 cm.

Thus, the highest amount we can cut off equally is 5 cm

learn more here: brainly.com/question/15808950

7 0

3 years ago