Well every time you roll you have the same probability of get it 1 out of 6, so this question don't have a specific answer
Answer:
Center of rotation
Step-by-step explanation:
=<span><span>(<span><span>2x</span>+3</span>)</span><span>(<span><span>4x</span>+<span>−2</span></span><span>)
</span></span></span><span>=<span><span><span><span><span>(<span>2x</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>2x</span>)</span><span>(<span>−2</span>)</span></span></span>+<span><span>(3)</span><span>(<span>4x</span>)</span></span></span>+<span><span>(3)</span><span>(<span>−2</span>)</span></span></span></span>
<span>=<span><span><span><span>8<span>x2</span></span>−<span>4x</span></span>+<span>12x</span></span>−6</span></span>
<span>=<span><span><span>8<span>x2</span></span>+<span>8x</span></span>−6</span></span>
Answer:
Yes, the set of numbers create a Pythagorean triple
Step-by-step explanation:
we know that
If a set of numbers create a Pythagorean triple, then the set of numbers must satisfy the Pythagorean Theorem
where
c is the greater side
a and b are the legs (perpendicular sides)
we have
substitute
----> is true
therefore
Yes, the set of numbers create a Pythagorean triple
The answer would be D - 1/6
This is because there are six sides to the die and just because he rolled all 3s before it does not mean he has a better chance to roll a 3 now.
Since there is only 1 3 on the six sided die there is a 1/6 chance he would roll a 3.
