- 2x (a+h)^2+4(a+h)-12

It’s you birthday and you bought a giant sandwich to feed all of your guests. The sandwich is 10 1/2 feet long and you need to f

Hoochie [10]

Answer: $1\dfrac{3}{4}\text{ feet}$

Step-by-step explanation:

Given: Length of sandwich = $10\dfrac12\text{ feet}=\dfrac{21}{2}\text{ feet}$

Total people = 14

If everyone gets a same sized piece , then length of each piece should be

$\dfrac{\text{ Length of sandwich}}{\text{Total people}}$

$=\dfrac{\dfrac{21}{2}}{14}\text{ feet}\\\\=\dfrac{21}{2\times14}\text{ feet}\\\\=\dfrac{7}{2\times2}\text{ feet}\\\\=\dfrac{7}{4}\text{ feet}\\\\=1\dfrac{3}{4}\text{ feet}$

Hence, length of each piece = $1\dfrac{3}{4}\text{ feet}$

3 0

3 years ago

6TH GRADE MATH I WILL GIVE BRAINLIEST HELP ASAP

dimaraw [331]

Answer:

Point D and It is equivalent to 75%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$