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amm1812
4 years ago
8

Which interval on the graph could be described as linear decreasing?

Mathematics
2 answers:
GenaCL600 [577]4 years ago
5 0
It's C, that is decreeing from y =4 to y=3
alexira [117]4 years ago
5 0

Answer:

C is decreasing

Step-by-step explanation:

Because it is going down.


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At a sale this week, a suit is being sold for $217. This is a 38% discount from the original price. What is the original price?
34kurt

Answer:

List price (original price) = $350

Discount amount ($ saved) = $133

Step-by-step explanation:

The list price is the sale price ($217) divided by the difference of 1 minus the result of the discount (38%) divided by 100.

3 0
3 years ago
Which best describes the range of numbers that satisfy the inequality x> 124?
nekit [7.7K]

Answer:

Answer shown below

Step-by-step explanation:

The range has a lower limit but no upper band limit

(124, infinity)

4 0
3 years ago
Find the value of c that makes the expression a perfect square trinomial.<br><br> x2 + 4x + c
masha68 [24]

the value of c that makes the expression a perfect square binomial is c=4 .

<u>Step-by-step explanation:</u>

Here we have , an expression x2 + 4x + c or , x^2 + 4x + c . We need to find  the value of c that makes the expression a perfect square binomial. Let's find out:

We have ,  x^2 + 4x + c

⇒ x^2+4x+c

⇒ x^2+2(2)x+c

Now , we know that (a+b)^2=a^2+2(a)(b)+b^2

Comparing above equation  , to  x^2+2(2)x+c we get ;

⇒  x^2+2(2)x+c            { c=2^2  }

⇒  x^2+2(2)x+2^2

⇒  (x+2)^2

Therefore , the value of c that makes the expression a perfect square binomial is c=4 .

7 0
3 years ago
Question 4 (20 points)
Pepsi [2]
16 there is the answer glad to help
4 0
3 years ago
Find the equation of the tangent to the circle x2 + y2 = 109 at point (-10,3)
konstantin123 [22]

Answer:

10x - 3y = -109 .

Step-by-step explanation:

x^2 + y^2 = 109

Implicit Differentiation:

2x + 2y.y' = 0

y' = -2x/2y = -x/y

So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.

Equation of the tangent:

y - y1 = m(x - x1)

y - 3 = 10/3(x + 10)

y - 3 = 10/3 x + 100/3

3y - 9 = 10x + 100

-109 + 3y = 10x

10x - 3y = -109  

4 0
3 years ago
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