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SCORPION-xisa [38]
3 years ago
8

A 1991 study at Ataturk University in Turkey showed that 50% of cats were right-pawed, 40% of cats

Mathematics
1 answer:
lawyer [7]3 years ago
8 0
Y Henry psn park Waco psn mic
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I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
The quadratic function g(x) = ax^2 + bx + c has the complex roots (-5+9i) and (-5-9i). (you may assume that a = -1) what is the
gavmur [86]

Answer:

  • b = -10, c = -106

Step-by-step explanation:

<h3>Given</h3>

<u>Quadratic function </u>

  • g(x) = ax^2 + bx + c

with the roots:

  • (-5+9i) and (-5-9i)
<h3>To find </h3>
  • b and c if a = -1
<h3>Solution</h3>

<u>As we know the sum of the roots is -b/a and the product of the roots is c/a. Substituting values and solving for b and c:</u>

  • (-5 + 9i) + (-5 - 9i) = -b/-1
  • -10 = b
  • b = -10

And

  • (-5 + 9i)(-5 - 9i) = c/-1
  • (-5)² - (9i)² = -c
  • 25 - 81(-1) = -c
  • - c = 25 + 81
  • - c = 106
  • c = -106

g(x) = -x² -10x - 106

4 0
3 years ago
A string is 7 yards long. Jeff needs 2 feet and Lori needs 15 feet of string. If they both cut their string, how much is left?
Aleksandr [31]
1\ yard=3\ feet\\\\7\ yard=3\cdot7=21\ feet\\\\21-2-15=4\\\\There\ are\ 4\ feet\ left
5 0
3 years ago
These three please, thank you!
Inessa05 [86]
The first one is 9/25
The second one is 29.44
The last one is 8
3 0
3 years ago
Read 2 more answers
Please help, I'm late on this and I can't put words with numbers well enough to make anything readable!!!
Andreyy89

so, what we do is, we multiply the value by a power of 10, that moves the recurring numbers to the left of the dot, in this case we want moved the "15", so we'll need two zeros, so we'll be using 100.


\bf 0.151515\overline{15}~\hspace{7em}x=0.151515\overline{15} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{|lll|ll} \cline{1-3} &&\\ 100\cdot x&=&15.1515\overline{15}\\ &&15+0.1515\overline{15}\\ &&15+x \\&&\\ \cline{1-3} \end{array}\implies 100x=15+x \\\\\\ 99x=15\implies x=\cfrac{15}{99}\implies \stackrel{simplified}{x=\cfrac{5}{33}}

4 0
3 years ago
Read 2 more answers
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