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ira [324]
3 years ago
13

2x < - x + 20 + 7 I don't get how to answer this question

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

ANSWER

X < 9

Solve

2x < - x + 20 + 7

2x < - x + 27 change the signs

2x + x < 27 add the like terms

3x < 27 divide by 3

x < 9

You might be interested in
Yogi is 6 years older than Michelle. The sum of their ages is 26. Write a system of linear equations to represent this informati
postnew [5]

Answer:

10 and 16, x+(x+6)=26

Step-by-step explanation:

Michelle has an age we don't know, so we put her age as x.

Yogi is 6 years older than her, so her age is x+6

Michelle=x

Yogi=x+6

we know both their ages equal 26. so we set it up as

x+(x+6)=26

combining like terms we get

2x+6=26

subtract 6 from both sides

2x=20

divide both sides by 2

x=10

now that we have the value for x, we plug it into their original ages

Michelle is 10, because her age is just x.

Yogi is 16, because her age is x+6

8 0
2 years ago
F = 0.272727...<br>100f = (100)(0.272727...)<br>100f = ?​
koban [17]

Answer:

<h2>100f = 27.272727...</h2>

Step-by-step explanation:

f = 0.272727...

100f = (100)(0.272727...)

100f = 27.272727...

6 0
2 years ago
I don’t know how to work i this out
snow_tiger [21]
Equation of the line:

y = -0.4x + 1.6

or
y =
- 2 x
5
+ 8
5
When x=0, y = 1.6
When y=0, x = 4



Mark brainliest please



Hope this helps you
8 0
2 years ago
An average computer mouse inspector can inspect 50 mice per hour. The 48 computer mice inspectors at a particular factory can on
Ronch [10]

Answer:  C. Yes, because -2.77 falls in the critical region .

Step-by-step explanation:

Let \mu be the population mean .

As per given , we have

H_0:\mu=50\\\\ H_a: \mu

Since the alternative hypothesis is left-tailed and population standard deviation is not given , so we need to perform a left-tailed t-test.

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

Also, it is given that ,

n= 48

\overline{x}=46

s= 10

t=\dfrac{46-50}{\dfrac{10}{\sqrt{48}}}=\dfrac{-4}{\dfrac{10}{6.93}}\\\\=\dfrac{-4}{1.443}\approx-2.77

Degree of freedom = df = n-1= 47

Using t-distribution , we have

Critical value =t_{\alpha,df}=t_{0.025,47}=2.0117

Since, the absolute t-value (|-2.77|=2.77) is greater than the critical value.

So , we reject the null hypothesis.

i.e. -2.77 falls in the critical region.

[Critical region is the region of values that associates with the rejection of the null hypothesis at a given probability level.]

Conclusion : We have sufficient evidence to support the claim that these inspectors are slower than average.

Hence, the correct answer is C. Yes, because -2.77 falls in the critical region

4 0
3 years ago
Can anyone help?? Please
natta225 [31]
3O=12/3   Divide both sides by 3.
/3

O=4
<span>
♢+2=5(4)
</span><span>♢+2=20
</span>    -2  -2      Subtract 2

<span> ♢=18
</span>
 2(4)+18=2∆
8+18=2∆
26=2∆
/2     /2      Divide by 2

∆=13
6 0
3 years ago
Read 2 more answers
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