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makkiz [27]
3 years ago
13

Pls explain

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

All answers are to 2 decimal places for accuracy.

1. Width is 27.71"

2. TV Size is 69.84"

3. Width is 51.96"

4. TV Size is 40.13"

5. Height is 26.06"

6.

Part 1: Diagonal is 61.91"

Part 2: Diagonal is 60.21"

Step-by-step explanation:

THe pythagorean theorem tells us that the sum of two legs of a triangle squared equal the hypotenuse squared.

<u>Note: </u>This applies for right triangles and the side opposite of the right angle is the hypotenuse

Also, to solve the first 5 problems, we can say:

Height^2 + Width^2 = TV \ Size^2

#1  32” TV height: 16” width: _____

Let width be w

16^2 + w^2 = 32^2\\w =\sqrt{32^2 - 16^2} \\w=27.71

Width is 27.71"

#2  _____ TV height: 34” width: 61”

Let tv size be t

34^2 + 61^2 = t^2\\t= \sqrt{34^2 + 61^2} \\t=69.84

TV Size is 69.84"

#3  60” TV height: 30” width: _____

Let width be w

30^2 + w^2 = 60^2\\w =\sqrt{60^2 - 30^2} \\w=51.96

Width is 51.96"

#4  _____ TV height: 20” width: 35”

Let tv size be t

20^2 + 35^2 = t^2\\t= \sqrt{20^2 + 35^2} \\t=40.31

TV Size is 40.13"

#5  52” TV height: _____ width: 45”

Let height be h

h^2 + 45^2 = 52^2\\h =\sqrt{52^2 - 45^2} \\h=26.06

Height is 26.06"

#6

<u>Part1:</u>

New dimensions would be

48+5 = 53" Width

27+3 = 30" Height

Let diagonal be d, so

d=\sqrt{53^2+32^2} \\d=61.91

Diagonal is 61.91"

<u>Part 2:</u>

New dimensions are:

48+3 = 51" Width

27 + 5 = 32" Height

Let diagonal be d, so

d=\sqrt{51^2+32^2} \\d=60.21

Diagonal is 60.21"

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