Rewrite the following rational expression with a new denominator as indicated 7/12 ;48
1 answer:
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The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is
Step-by-step explanation:
We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.
If -1, 1 and 3 are real zeros, it can be written as:
x= -1, x= 1, and x = 3
or x+1=0, x-1=0 and x-3=0
Finding polynomial by multiply these factors:
So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is
Keywords: Real zeros of Polynomials
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The simple answer (not using multiples of 2
(360°)) is
![= \sqrt[3]{125} ((cos( \frac{288}{3})) + isin(( \frac{288}{3}))) = 5(cos96 + isin96)](https://tex.z-dn.net/?f=%3D%20%20%5Csqrt%5B3%5D%7B125%7D%20%28%28cos%28%20%5Cfrac%7B288%7D%7B3%7D%29%29%20%2B%20isin%28%28%20%5Cfrac%7B288%7D%7B3%7D%29%29%29%0A%3D%20%205%28cos96%20%2B%20isin96%29)