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Gwar [14]
3 years ago
13

6x+5y+2z=41 4x-10z=-10 -x-2y+2z=-1

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​]
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