<span>8x^3y^2 = 4x^2y^2 (2x)
</span><span>20x^2y^4 = 4x^2y^2 (5y^2)
GCF = </span>4x^2y^2
There are several important information's already given in the question. Based on those information's the answer to the question can be easily deduced.
Number of cups of Oatmeal
required by Aunt Bess for making 6 dozen cookies = 3
Then
Number of cups of oatmeal
required by Aunt Bess for making 1 dozen cookies = (3/6)
= 1/2
So
Number of cups of oatmeal
required by Aunt Bess for making 18 dozen cookies = (1/2) * 18
= 9 cups
So Aunt Bess will require 9 cups of oatmeal for baking 18 dozen cookies. I hope the procedure is clear enough for you to undestand.
<u>Given</u>:
The given expression is 
We need to determine the values for which the domain is restricted.
<u>Restricted values:</u>
Let us determine the values restricted from the domain.
To determine the restricted values from the domain, let us set the denominator the function not equal to zero.
Thus, we have;

Taking square root on both sides, we get;



Thus, the restricted value from the domain is
Hence, Option A is the correct answer.
Answer:
-53
Step-by-step explanation:
If x=3 and y=-4
Plug the numbers into the equation
3 - (-4) - 3 + (-57)
Now solve the equation right to left
3 - (-4) = 7
7 - 3 = 4
4 - 57 = -53
So the answer is -53
Answer:
x² + 2x + [3\x - 1]
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
1| 1 1 -2 3
↓ 1 2 0
------------------
1 2 0 3 → x² + 2x + [3\x - 1]
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder, which in this case is a 3, so what you is set the divisor underneath the remainder of 3. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², 2 becomes <em>2x</em><em>,</em><em> </em>and the remainder of 3 is set over the divisor, giving you the other factor of <em>x² + 2x + [3\x - 1]</em>.
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