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Julli [10]
3 years ago
6

I will give 50 points and brainliest ​

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
Im guessing its 240
bh/2 is formula of triangle
b=16
h=30
16x30=480/2=240
vodka [1.7K]3 years ago
5 0

Answer:

240 m^2

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh

The base is 16 and the height is 30

A =1/2 ( 16*30)

240 m^2

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If A = 3x power 2+2y + 2 and B=6x power 2 - 8y + 1 then A+B and A-B​
ollegr [7]

Answer:

see explanation

Step-by-step explanation:

Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then

A + B

= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms

= 9x² - 6y + 3

-------------------------------

A - B

= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1

= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms

= - 3x² + 10y + 1

5 0
2 years ago
Which is the graph of y = 3/ x + 1 - 2?
garri49 [273]

Answer:

The second graph near the bottom with a Y-intercept of -1

7 0
3 years ago
Read 2 more answers
Find the value of x in each case:
diamong [38]

Answer:

Step-by-step explanation:

Sum of 3 angles of triangle= 180

147 + 4x + x = 180

147 +5x = 180

5x = 180 - 147

5x = 33

x = 33/5

x = 6•6 (Answer)

8 0
3 years ago
Read 2 more answers
A parking meter gives 30 minutes for each quarter and 6 minutes for each nickel
aleksley [76]

Answer:

B as we start with X intercept =0

Step-by-step explanation:

x= 10 x 6 = 60

(v= 1/6x = 6x x 10y) x= 60v

y=10

When x=0 then y = 0 when x= 10 we have 10 minutes each count

So the graph will go up by 10 to 60 on the x axis.

value of nickle=6  and units of 10 nickles have value of 60

But this is a measure of time using nickles for x.

and measure of quarters can then show a pattern of zero each time. y=mc+x = 0 when y=0 =  y=1x0+0 when x =6 and y=0

8 0
3 years ago
Consider the differential equation
Gennadij [26K]

The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.

The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.

This leaves us with the second choice. Recall that

1 + tan²(x) = sec²(x)

and the derivative of tangent,

(tan(x))' = sec²(x)

Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then

y' = sec²(x³/3 + 2) • x²

and substituting y and y' into the ODE gives

sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))

x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)

which is an identity.

So the solution is y = tan(x³/3 + 2).

4 0
2 years ago
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