Answer:
see explanation
Step-by-step explanation:
Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then
A + B
= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms
= 9x² - 6y + 3
-------------------------------
A - B
= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1
= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms
= - 3x² + 10y + 1
Answer:
The second graph near the bottom with a Y-intercept of -1
Answer:
Step-by-step explanation:
Sum of 3 angles of triangle= 180
147 + 4x + x = 180
147 +5x = 180
5x = 180 - 147
5x = 33
x = 33/5
x = 6•6 (Answer)
Answer:
B as we start with X intercept =0
Step-by-step explanation:
x= 10 x 6 = 60
(v= 1/6x = 6x x 10y) x= 60v
y=10
When x=0 then y = 0 when x= 10 we have 10 minutes each count
So the graph will go up by 10 to 60 on the x axis.
value of nickle=6 and units of 10 nickles have value of 60
But this is a measure of time using nickles for x.
and measure of quarters can then show a pattern of zero each time. y=mc+x = 0 when y=0 = y=1x0+0 when x =6 and y=0
The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.
The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.
This leaves us with the second choice. Recall that
1 + tan²(x) = sec²(x)
and the derivative of tangent,
(tan(x))' = sec²(x)
Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then
y' = sec²(x³/3 + 2) • x²
and substituting y and y' into the ODE gives
sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))
x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)
which is an identity.
So the solution is y = tan(x³/3 + 2).
