Lines <em>a</em> and <em>b</em> are parallel, so lines <em>p</em>, <em>q</em>, and <em>t</em> are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.
∠1 = 90° — corresponding angle to the right angle above it
∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°
∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)
∠4 = 112° — equal to angle 3
∠5 = 68° — equal to angle 2; supplementary to angle 4
∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle
∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6
∠8 = 124° — alternate interior angle with angle 7, hence its equal.
Replace x with the binomial a - 2.
f(a - 2) = [3(a - 2) + 5]/(a- 2)
f(a - 2) = [3a - 6 + 5]/(a - 2)
f(a - 2) = [3a - 1]/(a - 2)
f(a - 2) = (3a - 1)/(a - 2)
Done.
Here a photo of the answer. The first thing you have to do is split the figure into separate shapes. Find the area of the shapes, then add them all together.
Answer: see attachments
<u>Step-by-step explanation:</u>
Use Pythagorean Theorem to find the missing side (x² + y² = h²)
Use the following formulas to find the trig functions:

Answer

To prove


= 0.54


= 0.5

= 1.00
Now we find out the mid point of the 0.5 and 1.00 .

(Mid point is the point lies middle of a line segment .)
Mid point = 0.75
Thus

This shows o.54 lies between 0.5 and 1.00
This means 0.54 lies right to 0.5 and left from 1.00 .
Therefore
