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Alina [70]
3 years ago
12

I need help with adding decimals

Mathematics
2 answers:
nasty-shy [4]3 years ago
4 0
When you add the decimals it’s the same as regular adding. You line up the decimals and then add all the way across and when you get to the decimal carry it down
Temka [501]3 years ago
3 0
Line the decimals of your numbers up in a column

to add
3.5, 3.25, and .1

(any empty place becomes a zero)

3.50
3.25
0.10

6.85 would be the total.
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Please help me the picture is above I really need an answer please, I’ll mark as brainliest
sergeinik [125]

Answer:

Option d) The rocket was above 300 feet for approximately 2 seconds.

Explanation:

The rocket was above 300 for both 2 and 4 seconds.

Mark brainliest!!

7 0
4 years ago
20. Morgan got of the questions on a science test correct.
nadezda [96]

Answer:

ok I will need how many questions did she get correct

8 0
3 years ago
The volume of a box is 80 cubic feet with length x-3 and width x-1 and height x+5. What are the possible values of x? What are t
Kryger [21]

Answer:

  • the only possible value of x is 5
  • the dimensions are 2 × 4 × 10

Step-by-step explanation:

The cubic equation ...

  (x -3)(x -1)(x +5) = 80

has one real root: x = 5. Using that value for x, the dimensions become ...

  length = 5 - 3 = 2

  width = 5 - 1 = 4

  height = 5 + 5 = 10

The dimensions are (length, width, height) = (2, 4, 10).

_____

We cannot tell the thrust of the problem, since it has only one solution. Perhaps you're supposed to write the cubic in standard form and use the <em>Rational Root theorem</em> to find <em>possible values of x</em>. That form can be found to be ...

  (x -3)(x -1)(x +5) -80 = 0

  x³ +x² -17x -65 = 0

Descartes' rule of signs tells you there is one positive real root. The rational root theorem tells you possible rational roots are factors of 65:

  1, 5, 13, 65

We know that x must be greater than 3 (so all dimensions are positive). Thus <em>possible values of x are 5, 13, 65</em>, and we're pretty sure that 65 is way too large.

4 0
3 years ago
Solve for x in the equation x squared + 14 x + 17 = negative 96. x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i x = –7 ± 8
blagie [28]

Answer:

x=-7\pm8i

Step-by-step explanation:

we have

x^{2} +14x+17=-96

Equate to zero

x^{2} +14x+17+96=0

x^{2} +14x+113=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +14x+113=0

so

a=1\\b=14\\c=113

substitute in the formula

x=\frac{-14\pm\sqrt{14^{2}-4(1)(113)}} {2(1)}

x=\frac{-14\pm\sqrt{-256}} {2}

Remember that

i=\sqrt{-1}

so

x=\frac{-14\pm16i} {2}

x=-7\pm8i

7 0
3 years ago
Read 2 more answers
Amanda is 4 year older than Caroline. David is 2 years less than double Amanda’s age. Kene is 12 years younger than David. Toget
Sloan [31]
A is 34
C is 17
D is 66
K is 54
3 0
3 years ago
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