Consider a triangle ABC like the one below. Suppose that a =53, b=18, and A=130º. (The figure is not drawn to scale.) Solve the
triangle.
Carry your intermediate computations to at least four decimal places, and round
your answers to the nearest tenth.
If no such triangle exists, enter "No solution." If there is more than one solution, use the button labeled "or".
Carry your intermediate computations to at least four decimal places, and round
your answers to the nearest tenth.
If no such triangle exists, enter "No solution." If there is more than one solution, use the button labeled "or".
1 answer:
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Answer:
(- 7, - 4 )
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the turning point is
x = -
y = x² + 14x + 45 ← is in standard form
with a = 1, b = 14 , then
x = - = - 7
Substitute x = - 7 into the equation and evaluate for y
y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4
coordinates of turning point = (- 7, - 4 )
Answer:
=x
Step-by-step explanation:
0=(x-5)3
0=(3x-5)
5=3x
=x