9.1 *rounded tot he nearest 10th place*
SEE ATTACHED IMAGE TO OBSERVE THE GRAPH OF THE FUNCTION.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
<span>(5h^3 − 8h) + (−2h^3 − h^2 − 2h)
= 5h^3 - 8h - 2h^3 - h^2 - 2h
= 3h^3 - h^2 - 10h</span>
F(2)=4(2)+5
f(2)=8+5
f(2)=13