Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The mean of the sampling distribution is 
The sample size is n = 600
Generally the standard deviation is mathematically represented as

=>
=>
Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

=> 
Now add p to both side of the inequality
=> 
=> 
Now converting the probabilities to their respective standardized score
=>
=> 
=> ![P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%201%20-%20%5BP%28Z%20%5Cle%202.88%29%20-%20P%28Z%20%5Cle%20-2.88%29%5D)
From the z-table

and

So
![P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%201%20-%20%5B0.9980%20-%200.0020%5D)
=> 
That would be 10 x 10 x 10 = 1000
Answer:
The cost of one brownie is $0.75
Step-by-step explanation:
The given parameters are;
The number of pizza's Marcel bought = 4 pieces
The number of brownies Marcel bought = 2 brownies
The amount Marcel paid = $18.50
The number of pizza's Morgan bought = 3 pieces
The number of brownies Morgan bought = 2 brownies
The amount Morgan paid = $14.25
Let x represent the cost of a pizza and y represent the cost of a brownie, we have;
4·x + 2·y = $18.50...(1)
3·x + 2·y = $14.25...(2)
Subtracting equation (1) from equation (2) gives;
4·x + 2·y - (3·x + 2·y) = $18.50 - $14.25 = $4.25
4·x - 3·x + 2·y - 2·y = $4.25
x = $4.25
The cost of a pizza = x = $4.25
4·x + 2·y = $18.50
2·y = $18.50 - 4·x = $18.50 - 4×$4.25 = $1.5
y = $1.5/2 = $0.75
y = $0.75
The cost of a brownie = $0.75
Answer:
1) 2m + 3m2 - 4m=7
7) 3m2 – 2m + 4m= 11
8) 20 + 109 + 39 - 4= 164
3) 2m + 4m - 3m2= -3
9) 4xy + x + 2xy= 0
4) 2y + 14x - 7x + 9y= 18
10) 6m2 - 6m - 9m2= -51
Step-by-step explanation:
78.33 APEX.....................................................