Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
Answer:
<h3>
2642km</h3>
Step-by-step explanation:
Given the map coordinates o a bird during travel from Vermont at cordinate (63,45) toto Venezuela at map coordinates (67,10). In order to know how far the bird has travelled, we need to find the distance between the two coordinates first using the formula;
D = 
Given x₁ = 63, y₁ = 45, x₂ = 67, y₂ = 10

If each map coordinate represents 75 kilometers, then the birds distance in km will be 75*35.2278 = 2642.087km
Hence the birds distance in km will be 2642km to the nearest kilometers
Answer:
C. -2x+10
Step-by-step explanation:
When you multiply a negative with a negative, it becomes a positive.
Answer: 0
Step-by-step explanation: