Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
0.7 / 100 = 0.007 or 0.007 x 100 = 0.7 hope this helps
Answer:
the patters is that they are multiple of 7.. so next number is 42.
which means option D <u>The missing number is even</u> is correct..
The factors of 4 are 1, 2, and 4 .
The factors of 9 are 1, 3, and 9 .
Answer:
Twenty-three thousand five hundred seventy-nine
Step-by-step explanation: