Question

Find P 20 of the following arithmetic sequence: 206, 212, 218, 224....

Answer 1

Answer:

$p_{20} = 1.25528$

P₀ = 206 and difference d = 6

Step-by-step explanation:

Step(i):-

Given that the arithmetic sequence

                 206,212,218,224,.....

P₀ = 206 and difference d = 212-206 = 6

The $n^{th}$ term of the sequence

   $t_{n} = ar^{n-1}$

Step(ii):-

The $n^{th}$ term of the sequence

   $P_{n} = ar^{n-1}$

Put n=20

$P_{20} = 206 ( 6) ^{20-1}$

$p_{20} = 1.25528$