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irakobra [83]
3 years ago
7

Which rule describes the relationship between the x- and y- coordinates on the following graph?​

Mathematics
1 answer:
arlik [135]3 years ago
4 0
Where is the pic of graph ?
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A researcher expects a treatment to produce an increase in the population mean. The treatment is evaluated using a one tailed hy
Shkiper50 [21]

Answer:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

Step-by-step explanation:

State the null and alternative hypotheses to be tested  

On this case we can assume that the researcher conduct a one right tailed test hypothesis like on this way:  

Null hypothesis:\mu \leq \mu_o  

Alternative hypothesis:\mu > \mu_o

The statistic for this case is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

On this case we have the value for z score given z =+1.85

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05,0.01. The next step would be calculate the p value for this test.  

Since is a one right tail test the p value would be:  

p_v =P(z>1.85)=1-P(Z  

If we compare the p value obtained and the significance level given \alpha=0.05,0.01 we can take a decision:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

YES, since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level. And for the significance level 0.05 we have that p_v and we can reject the null hypothesis.

B) The researcher should reject the null hypothesis with either a = .05 or a = .01.

No since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level

C) The researcher should fail to reject H0 with either a = .05 or a = .01.

No, for the significance level of 0.05 we reject the null hypothesis since p_v

D) This cannot be answered without additional information.

No, we have enough info to answer the question

4 0
4 years ago
263/4 options 65r2 64r7 65 65r3
Reika [66]

Answer:

65R3

Step-by-step explanation:

260/4 is a whole number, so then there would be a remainder 3. The only one with a r3 is D.

Hope this helps :D

4 0
3 years ago
How do you know if the factors will have negatives or positives in them?
harina [27]

When using factoring by grouping, the replacement terms will both have the same sign of the original middle term. If the last term is negative, then the signs of the factors will have one of each sign with the “stronger” number (the larger absolute value) matching the middle term. hope this helps
8 0
3 years ago
Coach Stevens needs to purchase sprinklers to water the baseball field. The standard distance between bases is 90 feet and the i
egoroff_w [7]
If you need the geometry and trigonometry I'll post those.  Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span> <span> <span> 66.78</span> </span>f</span>eet

Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.

I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.


6 0
3 years ago
Three vectors A, B, C in three-dimensional space satisfy the following properties
wlad13 [49]

Answer:

\frac{7}{8}\pi

Step-by-step explanation:

observe

||a–b+c|| = ||a+b+c||

(a-b+c)² = (a+b+c)²

(a+b+c)² – (a-b+c)² = 0

((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0

(2a+2c)(2b) = 0

(a+c)b = 0

a•b + c•b = 0

||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

\cos(\theta)=-\frac{||a||\times ||b|| \times \cos(\frac{\pi}{8})}{||c||\times ||b||}=-\cos(\frac{\pi}{8})\\ \theta=\frac{7}{8}\pi

3 0
4 years ago
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