Answer: the x-intercept is (-10,0), the y-intercept is (0,45/2)
Explanation:
First, we need to determine the function describing the line.
From the table, it is obvious that the y values increase by 9 every increase of 4 of the x values. So, the slope is 9/4 and the function looks like this:
with the y-intercept (or bias) b still unknown. This can be determined by using one of the point from the table, like so:
The above function form makes it easy to read off the y-intercept, which is (0,45/2) or (0,22.5). The x-intercept is obtained by setting y = 0 and solving for x:
The x-intercept is (-10,0)
The variables have a negative association/correlation, because when one value increases (ex: x) the other decreases (see y)
If you would put a line through the dataset most of the points would be quite a bit off the line so the association is only moderate and not strong
so the answer is it is a "moderate negative association"
Answer:
5 and 6
Step-by-step explanation:
The square root of 27 is 5.19615242271 , which is more than 5 but less then 6, therefore is between 5 and 6.
<em />
<em />
<em />
<em />
<em />
<em />
<em>Hope this helped (: Can you please mark as brainliest?</em>
The approximation to estimate will be 0.2498
To simplify the function, we need to know some basic identities involving exponents.
1. b^(ax)=(b^x)^a=(b^a)^x
2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)
Now simplify f(x), where
f(x)=(1/3)*(81)^(3*x/4)
=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]
=(1/3)(3^(4*3*x/4) [ rule 1 above ]
=(1/3) (3^(3*x)
=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]
(A) Initial value is the value of the function when x=0, i.e.
initial value
= f(0)
=(1/3)(3^(3x))
=(1/3)(3^(3*0))
=(1/3)(3^0)
=(1/3)(1)
=1/3
(B) the simplified base base is 3 (or 27 if the other form is used)
(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).
(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).
