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3 years ago

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The organizer of a television show must select 5 people to participate in the show. The participants will be selected from a lis

t of 30 people who have written in to the show. If the participants are selected randomly, what is the probability that the 5 youngest people will be selected?

2 answers:

Crazy boy [7]3 years ago

7 0

Answer:

The correct answer to this is 1/142,506

Lemur [1.5K]3 years ago

3 0

5/30 But you should say how many young people there are because for all we know all 30 could be young

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Answer:

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Step-by-step explanation:

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9514 1404 393

Answer:

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Step-by-step explanation:

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Corresponding angles are congruent, so we have ...

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2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

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2 years ago