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777dan777 [17]
3 years ago
13

Solve x^2+2x+7=0 using the quadratic formula.

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

x=-1\pm \sqrt{6}i

Step-by-step explanation:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(2)\pm\sqrt{2^2-4(1)(7)}}{2(1)}

x=\frac{-2\pm\sqrt{4-28}}{2}

x=\frac{-2\pm\sqrt{-24}}{2}

x=\frac{-2\pm\sqrt{-1*24}}{2}

x=\frac{-2\pm\sqrt{-1}\sqrt{24}}{2}

x=\frac{-2\pm i\sqrt{4*6}}{2}

x=\frac{-2\pm i\sqrt{4}\sqrt{6}}{2}

x=\frac{-2\pm2i\sqrt{6}}{2}

x=-1\pm \sqrt{6}i

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Select the expression that is equivalent to (2x^2 +5)-5/2
anyanavicka [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve :

  • {(2 {x}^{2}  + 5) }^{  - \frac{5}{2} }

  • \dfrac{1}{{(2 {x}^{2}  + 5) }^{ \frac{5}{2} } }

  • \dfrac{1}{ \sqrt{( 2{x}^{2}  + 5) {}^{5} } }

therefore, the correct choice is :

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3 0
3 years ago
If the diameter of the sphere is increased by 20% . By what % does its curved surface area increase?
mihalych1998 [28]

Answer:

Curved surface area of sphere = 2πr × 2r=4πr^2;

The new diameter is 120/100 from the old diameter;

2R = (120/100)x(2r);

So, R = 1.2 x r;

Curved surface area of new sphere = 4πR^2 = 4π(1.2xr)^2= 4πr^2x1.44= curved surface of old sphere x (144%);

Finnaly, the increase is 44%.

Step-by-step explanation:

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3 years ago
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SpyIntel [72]
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3 years ago
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Answer: you have it right

Step-by-step explanation:

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What is the answer 8/5÷(6/15)
Norma-Jean [14]

Answer: 4

Step-by-step explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes 8/5 x 15/6

For fraction multiplication, multiply the numerators and then multiply the denominators to get 8x15/5x6 = 120/30

Since 120 divided by 30 equals 4 then, 120/30 = 4

Therefore 8/5, 6/15 = 4

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4 years ago
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