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Trava [24]
4 years ago
6

Find the distance between point I and point J

Mathematics
2 answers:
Brrunno [24]4 years ago
5 0

Answer:

Step-by-step explanation:

hello :

distance between I(-2,-3) an J (-7,-3) is :  

IJ= √((X2 - X1)² + (Y2 - Y1)²)

in this exercice : X1 = -2   X2 = -7  Y1 = -3    Y2 = -3   continue .....calculate IJ

MakcuM [25]4 years ago
4 0

Step-by-step explanation:

Coordinate of I (-2,-3)

Coordinate of J (-7,-3)

Distance between IJ ,

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }

=  \sqrt{ {( - 7 + 2)}^{2}  + {( - 3 + 3)}^{2} }

\sqrt{ {( - 5)}^{2} }  =5 \: units

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Given the line 2y=−3x+5 , determine the relationship to the line below. Is it perpendicular, parallel, intersecting (but not per
aliya0001 [1]

Answer:

  coinciding

Step-by-step explanation:

If you divide the second equation by 3, you get the first equation. They describe the same line, so the lines are <em>coinciding</em>.

6 0
3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

5 0
3 years ago
Find the slope of the line that passes through (6, 9) and (4, 14).
Veronika [31]

Answer:

The slope is -5/2 :)

Step-by-step explanation:

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1/4=2/8 & 1/8+2/8=3/8
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