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sattari [20]
3 years ago
13

What is 0.1x = 0.2(x+2)

Mathematics
2 answers:
krek1111 [17]3 years ago
8 0
0.1x=0.2(x+2)\ \ \ |mltiply\ both\ sides\ by\ 10\\\\10\cdot0.1x=10\cdot0.2(x+2)\\\\1x=2(x+2)\ \ \ |use\ distributive\ property:a(b+c)=ab+ac\\\\x=(2)(x)+(2)(2)\\\\x=2x+4\ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\x-2x=2x-2x+4\\\\-x=4\ \ \ \ |change\ signs\\\huge\boxed{x=-4}

check\\subtitute\ the\ value\ of\ x\ to\ the\ equation:\\L_s=0.1\cdot(-4)=-0.4\\R_s=0.2(-4+2)=0.2(-2)=-0.4\\\\L_s=R_s\ \ \ |correct\ :)
Paladinen [302]3 years ago
7 0
0.1x = 0.2(x + 2)

First, divide both sides by 0.1 / Your problem should look like: x = 2(x + 2)
Second, expand. / Your problem should look like: x = 2x + 4
Third, subtract 2x from both sides. / Your problem should look like: x - 2x = 4
Fourth, simplify x - 2x to -x. / Your problem should look like: -x = 4
Fifth, multiply both sides by -1. / Your problem should look like: x = -4

Answer: x = -4

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Factorization is a method of writing numbers as the product of their factors or divisors.

<em><u>Solution:</u></em>

<em><u>Factorisation:</u></em>

Factorization is a method of writing numbers as the product of their factors or divisors.

In other words we can say, Finding what to multiply together to get an expression.

It is like "splitting" an expression into a multiplication of simpler expressions.

<em><u>Methods of factorisation:</u></em>

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<em><u>Factoring out the GCF:</u></em>

This methods means that factoring out common factors

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This can be used when each term in given expression shares a common factor

<em><u>The sum-product pattern</u></em>

A quadratic equation may be expressed as a product of two binomials

For example:

x^2 + 7x + 12 = (x + 3)(x + 4)

This method can be used for quadratic equations of form ax^2 + bx + c = 0

<em><u>The grouping method</u></em>

If the polynomial is of the form  ax^2 + bx + c and there are factors of ac that add up to b , we can use this method

For example:

2x^2 + 7x + 3\\\\2x^2 + 6x + 1x + 3\\\\2x(x + 3) + 1(x + 3)\\\\(x + 3)(2x + 1)

<em><u>The perfect square trinomial pattern</u></em>

If the first and last terms are perfect squares and the middle term is twice the product of their square roots , we can use this method

For example:

x^2 + 10x + 25\\\\(x + 5)^2

<em><u>The difference of squares pattern</u></em>

If the expression represents a difference of squares, we can use this method

Because a^2 - b^2 = (a + b)(a - b)

For example:

x^2 - 25\\\\x^2 - 5^2\\\\(x + 5)(x - 5)

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