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3 years ago

Can you help me please?

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

The range of a function are the possible outputs, here { 2, 6, 8 }.

Answer: D

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X+y=7;x+2y=11 Solve by substitution steps must.

Tpy6a [65]

Answer:

Step-by-step explanation:

x + y = 7 ------------(I)

y = 7 - x ------------(II)

x + 2y = 11 --------------(III)

Substitute y = 7 - x in equation (III)

x + 2 * (7 -x) = 11

x + 2*7 - 2*x = 11

x + 14 - 2x = 11

x - 2x + 14 = 11

- x + 14 = 11

Subtract 14 from both side

-x = 11 - 14

-x = -3

Multiply both sides by (-1)

x = 3

Substitute x=3 in equation (II)

y = 7 - 3

y = 4

8 0

2 years ago

Read 2 more answers

Solve for z. -2 (52 - 4) +62 = -4

Masja [62]

Answer:

if you learned, PEMDAS then it be easier! soo I'll help.

Step-by-step explanation:

-2 ( 52- 4 ) is 48. 48 + 62= 110

if that's wrong, then I'm sorry!

——

110

6 0

3 years ago

Divide 30 in a ratio of 3:2

Sergeeva-Olga [200]

$Other\ method:\\\\x;y-searches\\\\ \left\{\begin{array}{ccc}x+y=30&|subtract\ y\ from\ both\ sides\\x:y=3:2\end{array}\right\\\left\{\begin{array}{ccc}x=30-y&(1)\\\frac{x}{y}=\frac{3}{2}&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\\frac{30-y}{y}=\frac{3}{2}\ \ \ \ |cross\ multiply\\\\(3)(y)=(2)(30-y)\\3y=60-2y\ \ \ \ |add\ 2y\ to\ both\ sides\\5y=60\ \ \ \ |divide\ both\ sides\ by\ 5\\\boxed{y=12}$

$Put\ the\ value\ of\ y\ to\ (1):\\x=30-12\\\boxed{x=18}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=18\\y=12\end{array}\right\to18:12}$

4 0

3 years ago

Read 2 more answers

7 x what = 315?????????????

Allisa [31]

Answer:

7 × x = 315

x = 315 ÷ 7

x = 45

45 is the answer.