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malfutka [58]
3 years ago
5

A package of beans in cans costs $32.50. How much does each can cost if there is 20 cans in the package?​

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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Are 4/7 and 12/21 equivalent fractions? Why or why not?
Anni [7]

Answer:

Yes

Step-by-step explanation:

12/21 simplified is 4/7. if you divide the numerator (12) by 3 and the denominator (21) by 3, you get 4 and 7, or 4/7 if you put it together.

5 0
3 years ago
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A dairy farm had 9 pastures and 630 cows. The same number of cows are placed in each pasture. How many cows are in each pasture?
rjkz [21]

Answer:


Step-by-step explanation:

if a dairy farm has 630 cows and the same number of cows are placed in each pasture the total number of cows in each pasture is 630

8 0
4 years ago
Express the polynomial z^2-z^4+2z^2 in standard form and then classify it.
zalisa [80]
Write this as -z⁴+3z²=-z²(z²-3). This is a quadratic in z². It could also be called a quadratic quartic.
As a polynomial it is fourth degree.
8 0
3 years ago
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Dairy cows at large commercial farms often receive
IrinaK [193]

Answer:

a) The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

b) They would need to use a confidence level of 94.52%.

Step-by-step explanation:

a)

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. So

M = 2.575*\frac{2.25}{\sqrt{12}} = 1.65

The lower end of the interval is the mean subtracted by M. So it is 28-1.65 = 26.35 kg/d

The upper end of the interval is the mean added to M. So it is 28 + 1.65 = 29.65 kg/d.

The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

(b) If the farms want the confidence interval to be no wider than 1.25 kg/d, what level of confidence would they need to use?

Now we want to find the value of z when M = 1.25. So:

1.25 = z*\frac{2.25}{\sqrt{12}}

0.6495z = 1.25

z = 1.92, that has a pvalue of 0.9726.

So the confidence level should be 1 - 2*(1-0.9726) = 0.9452

They would need to use a confidence level of 94.52%.

3 0
3 years ago
What number lies between 7x8/10=
zzz [600]
The number that lies between that is 7
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3 years ago
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