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4 years ago

Find the solution of pair of equation y=0 and y= -6

Mathematics

2 answers:

Norma-Jean [14]4 years ago

5 0

Answer:

Step-by-step explanation:

there is no soltion because it is not intersects

Crank3 years ago

3 0

Answer:

No solution as it will not intersect.

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Y = 4x - 6

Studentka2010 [4]

Answer:

B) 2x - 12x - 18 = 8

Step-by-step explanation:

2x - 3y = 8

If y = 4x - 6, then substitute and solve:

2x - 3(4x - 6) = 8

2x - 12x - 18 = 8

10x - 18 = 8

10x = 8 + 18

10x = 26

x = 26/10

x = 2.6

y = 4(2.6) - 6

y = 10.4 - 6

y = 4.4

8 0

3 years ago

Simplify radical -81

Solnce55 [7]

Step-by-step explanation:

-81

$\sqrt{ - 1} \: \times \sqrt{81}$

$\sqrt{ - 1} = i$

$i \times \sqrt{9 {}^{2} }$

$i \times 9$

$9i$

5 0

3 years ago

Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th

bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0

3 years ago

SOLVE FOR M. please :)

STatiana [176]

Answer:

$m = - 28$

Step-by-step explanation:

$\frac{ - 3}{7} m = 12$

$\frac{ - 7}{3} ( \frac{ - 3}{7})m = \frac{ - 7}{3} \times 12$

$\frac{ - 1}{3} ( - 3)m = \frac{ - 7}{3} \times 12$

$- 1( - 1)m = \frac{ - 7}{3} \times 12$

$1 \times m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} (3 \times 4)$

$m = - 28$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18

gavmur [86]

Answer:

The weight of cat is 14 pounds and the weight of kitten is 4 pounds.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be $x.$

And the kitten weight = $\frac{x}{2} -3$

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

$(x)+(\frac{x}{2}-3)=18$

$x+\frac{x}{2} -3=18$

$\frac{2x+x-6}{2} =18$

$\frac{3x-6}{2} =18$

Multiplying both sides by 2 we get:

$3x-6=36$

Adding both sides by 6 we get:

$3x=42$

Dividing both sides by 3 we get:

$x=14\ pounds.$

The weight of cat = 14 pounds.

Substituting the value of $x$ to get the kitten's weight:

$\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.$

The kitten's weight = 4 pounds.

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

7 0

3 years ago

Find the solution of pair of equation y=0 and y= -6​

Find the solution of pair of equation y=0 and y= -6