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dedylja [7]
3 years ago
14

64 = x3 what value of x makes this equation true ?

Mathematics
2 answers:
RUDIKE [14]3 years ago
8 0

Answer:

x = 3

The cube root of 64 is 4 because 4 x 4 x 4 = 64.

Cube roots have 3 identical factors, while square roots have 2 identical factors.

Hope this helps you!

musickatia [10]3 years ago
5 0

Answer:

x = 4.

Step-by-step explanation:

64 = x^3

x^3 = 64

\sqrt[3]{x^3}  = \sqrt[3]{64}

\sqrt[3]{x^3}  = \sqrt[3]{4 * 4 * 4}

\sqrt[3]{x^3}  = \sqrt[3]{4^3}

x = 4.

Hope this helps!

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2 years ago
Show all work to factor x^4 − 10x^2 + 9 completely.
elena-14-01-66 [18.8K]
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2 years ago
What is the greatest common factor of 4-6a
strojnjashka [21]

Answer:

The GFC of 5 and 6 is 2.

Step-by-step explanation:

Hope this helps :))

8 0
3 years ago
Andre says 10x + 6 and 5x + 11 are equivalent because they both equal 16 when x is 1. Do you agree with Andre?​
Serga [27]

Answer:

No, They are not equivalent

Step-by-step explanation:

The two expressions are only said to be equivalent if they are the same regardless of whatever value the variable(s) is.

The variable in this question is x.

To prove this, we equate both expressions:

10x + 6 = 5x + 11

10x - 5x = 11 - 6\\\\\\5x = 5\\\\\\x = 1

This shows that they have the same value ONLY when x is 1.

This is why Andre says that they are equivalent, but they are not.

8 0
3 years ago
Whats the answer to -3a+8-8(7-2a)​
Serga [27]

Answer:3.1875

Step-by-step explanation: Simplifying

-3 + 8 + -8(7 + -2a) = 0

-3 + 8 + (7 * -8 + -2a * -8) = 0

-3 + 8 + (-56 + 16a) = 0

Combine like terms: -3 + 8 = 5

5 + -56 + 16a = 0

Combine like terms: 5 + -56 = -51

-51 + 16a = 0

Solving

-51 + 16a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '51' to each side of the equation.

-51 + 51 + 16a = 0 + 51

Combine like terms: -51 + 51 = 0

0 + 16a = 0 + 51

16a = 0 + 51

Combine like terms: 0 + 51 = 51

16a = 51

Divide each side by '16'.

a = 3.1875

Simplifying

a = 3.1875

5 0
3 years ago
Read 2 more answers
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