The answer will be 2. the gcf of the equation is 2 because 2 goes into 10 by 5 and into 4 by 2 leaving you with 2(5b^2+2a^3).
Answer:
5 times as large
Step-by-step explanation:
You can think of "10^5" as "green marbles" if you like. Then your question is ...
5 green marbles is how many times as large as 1 green marble.
Hopefully, the answer is all too clear: it is 5 times as large.
_____
In math terms, when you want to know how many times as large y is as x, the answer is found by dividing y by x:
y/x . . . . . tells you how many times as large as x is y.
Here, that looks like ...
Answer: the correct option is
(D) The imaginary part is zero.
Step-by-step explanation: Given that neither a nor b are equal to zero.
We are to select the correct statement that accurately describes the following product :
We will be using the following formula :
From product (i), we get
![P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.](https://tex.z-dn.net/?f=P%5C%5C%5C%5C%3D%28a%2Bbi%29%28a-bi%29%5C%5C%5C%5C%3Da%5E2-%28bi%29%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2i%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2%5Ctimes%20%28-1%29~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7Di%5E2%3D-1%5D%5C%5C%5C%5C%3Da%5E2%2Bb%5E2.)
So, there is no imaginary part in the given product.
Thus, the correct option is
(D) The imaginary part is zero.
You put the 15x + 100 on the angle CEB instead of CED. If you put it in the right spot, it should work out fine since they are vertical angles.
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
