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marishachu [46]
3 years ago
12

What is the total cost the company pays for shipping the microscope

Mathematics
1 answer:
kkurt [141]3 years ago
6 0
Im sorry, I yried to help, but I cant figure it out
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Find the area of the shape
aliina [53]

Answer:

72 yd^2

Step-by-step explanation:

Separate the shape into a square and a rectangle. Figure out the measurements of each shape then add the total.

4 0
3 years ago
What is the value of f(x) when x=3?<br> -3<br> o -2<br> o 1<br> O
Svetach [21]
The answer is -3 darling
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3 years ago
What are the ordered pairs of the
Sholpan [36]

Answer:

its definitvely 6

Step-by-step explanation:

2 by 4 by the 3 empfs and by the 123 divided by the 360 and by the iscoceles and the 4 cohedrons

5 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
Simplify √5 • √8. <br><br> A.)2√10 <br> B.)4√10 <br> C.)√40 <br> D.)√13
tresset_1 [31]

Answer:

Simplify the radical by breaking the radical  up into a product of known factors.

2 √ 10

Step-by-step explanation:

5 0
3 years ago
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